Since the speeds of the two machines are tied together by their synchronous bond, the increase in fuel to the machine 1 does not make it run faster.
Alternatively, it utilises the increased power input for carrying more load than machine 2.
This is possible because of angular advance of machine 1 with respect to machine 2.
Here E1 advances E2 by an angle α. The resultant voltage Er sets up a current Isy which is almost in phase with E1.
Hence, power per phase of machine 1 is increased by an amount =E1 Isy whereas that of machine 2 is decreased by the same amount.
Since Isy has no reactive component, the increase in fuel supply does not disturb the division of KVAR but it increases KW of machine 1 and decreases that of machine 2.
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