If 200w, 100 w and 60 w lamps connected in series with 230V AC ,
which lamp glow brighter? Each lamp voltage rating is 230V.
§ Each bulb when
independently working will have currents (W/V= I)
§ For 200 Watt Bulb
current (I200) =200/230=0.8696 A
§ For 100 Watt Bulb
current (I100) =100/230=0.4348 A
§ For 60 Watt Bulb
current (I60) =60/230=0.2609 A
§ Resistance of each
bulb filament is (V/I = R)
§ For 200 Watt Bulb
R200= 230/0.8696= 264.5 ohms
§ For 100 Watt Bulb
R100= 230/0.4348 = 528.98 ohms and
§ For 60 Watt Bulb R60=
230/0.2609=881.6 ohms respectively
§ Now, when in series,
current flowing in all bulbs will be same. The energy released will be I2R
§ Thus, light output
will be highest where resistance is highest. Thus, 60 watt bulb will be
brightest.
§ The 60W lamp as it
has highest resistance & minimum current requirement.
§ Highest voltage drop
across it X I [which is common for all lamps] =s highest power.
§ Note to remember:
§ Lowest power-lamp has
highest element resistance.
§ And highest
resistance will drop highest voltage drop across it in a Series circuit
§ And highest
resistance in a parallel circuit will pass minimum current through it. So
minimum power dissipated across it as min current X equal Voltage across =s min
power dissipation
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